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The question is a bit unclear, but I will take a stab at figuring it out.
I guess the idea here is to generate a pattern (and reverse it) for each window. You can do it this way:
>>> import itertools
>>> print(itertools.product(‘a’, ‘b’, ‘c’))

[(‘a’, ‘a’, ‘a’),
(‘a’, ‘a’, ‘b’),
(‘a’, ‘a’, ‘c’),
(‘a’, ‘b’, ‘a’),
(‘a’, ‘b’, ‘b’),
(‘a’, ‘b’, ‘c’),
(‘a’, ‘c’, ‘a’),
(‘a’, ‘c’, ‘b’),
(‘a’, ‘c’, ‘c’)]

Now, you can create a function to combine these two lists, instead of hard-coding each window in a separate list. You can use the zip function for this, as follows:
>>> def window(seq):
… return [n for n, s in zip(seq, itertools.product(‘abc’, ‘def’))]

>>> def combine(w1, w2):
… return list(window(w1 + w2))

>>> combine(‘a’, ‘a’)
[‘a’] >>> combine(‘a’, ‘b’)
[‘a’, ‘b’] >>> combine(‘a’, ‘c’)
[‘a’, ‘c’]

Now, finally, you can just “zip” every window with every other window, and split the resulting list back in two. You can do this with itertools.product() and a list comprehension, as follows:
>>> def combine(*w1s):
… s1 = [n for w1, n in itertools.product(*w1s)] … s2 = [n for w2, n in itertools.product(*w1s)] … return [l + s for l in s1 for s in s2]

>>> combine(‘a’, ‘a’, ‘a’)
[‘a’, ‘a’, ‘a’] >>> combine(‘a’, ‘a’, ‘b’)
[‘a’, ‘b’, ‘a’] >>> combine(‘a’, ‘b’, ‘a’)

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